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If 2ysinx(dy)/(dx)=sin2x-y^2 cosx and at...

If `2ysinx(dy)/(dx)=sin2x-y^2 cosx and at x=pi/2,y=1`, then

A

`y^2=1+cos x`

B

`y=sin^2x`

C

`y^2sinx=1+cos x`

D

`y^2=sin x`

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The correct Answer is:
D
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