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A square of side 20 cm is enclosed by a ...

A square of side 20 cm is enclosed by a surface of sphere of 80 cm radius. Square and sphere have the same centre. Four charges `+4xx10^(-6)C`,
`-5xx10^(-6)C,-3xx10^(-6)C,+6xx10^(-6)C` are located at the four corners of a square then total flux from spherical surface in `N-m^(2)C^(-1)` will be

A

zero

B

`48pixx10^(3)`

C

`72pixx10^(3)`

D

`36pixx10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`phi_(e)=(Sigmaq)/(epsilon_(0))`
Here `Sigmaq=2xx10^(-6)C`
Hence `phi_(2)=72pixx10^(3)`
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