The molecules of two gases have radii in ratio `3/2`. Assuming that both the gases are under identical condictions and have equal volumes, calculate the ratio of the mean free paths of the molecules .

Answer

`00.44`

Explanation

Mean free path of a gas molecule
`lamda=1/(sqrt(2)pid^(2)n)`
As all the physical conditions are identical,
`lamda prop 1/(d^(2))`
`:.(lamda_(1))/(lamda_(2))=((d_(2))/(d_(1)))^(2)=[((1xx2)\\"AA")/((1.5xx2)\\"AA")]^(2)`
`=(1/(3//2)))^(2)`
`=4/9`
`:.(lamda_(1))/(lamda_(2))=0.44`