Calculate the volume of one mole of any gas at STP and at room temperature (300K) with the same pressure 1 atm.

Explanation

Here STP means standard temperature
`(T=273K" or "0^(@)C)` and pressure (P=1 atm or 101.3 kPa)
We can use ideal gas equation `V=(muRT)/(P)`.
Here `mu=1` mol and `R=8.314J//mol.K`.
By substituting the values
`V=((1mol)(8.314(J)/(mol)K)(273K))/(1.013xx10^(5)Nm^(-2))`
`=22.4xx10^(-3)m^(3)`
We know that 1 Litre (L)`=10^(-3)m^(3)`. so we can conclude that 1 mole of any ideal gas has volume 22.4 L.
By multiplying 22.4 L by `(300K)/(273K)` we get the volume of one mole of gas at room temperature. it is 24.6 L.