The power radiated by a black body A is `E_(A)` and the maximum energy radiated was at the wavelength `lamda_(A)`. The power radiated by another black body B is `E_(B)=NE_(A)` and the radiated energy was at the maximum wavelength, `(1)/(2)lamda_(A)`. what is the value of N?

Explanation

According to Wien.s displacement law
`lamda_(max)T=`constant for both object A and B
`lamda_(A)T_(A)=lamda_(B)T_(B)`. Here `lamda_(B)=(1)/(2)lamda_(A)`
`(T_(B))/(T_(A))=(lamda_(A))/(lamda_(B))=(1)/((1)/(2))=2`
`T_(B)=2T_(A)`
From stefan-Boltzmann law
`(E_(B))/(E_(A))=((T_(B))/(T_(A)))^(4)=(2)^(4)=16=N`
Object B has emitted at lower wavelength compared to A. so the object B would have emitted more energetic radiation than A.