Check the dimensional of the wave y = sin(x-vt). If it is dimensionally wrong, write the above equation in the correct form.

Explanation

Dimensionally it is not correct. we know that y = sin(x-vt) must be a dimensionless quantity but x-vt has dimension. The correct equation is y= sin (k x-`omega`t), where k and `omega` have the dimensions of inverse of length and inverse of time respectively. The sine functions and cosine functions are periodic functions with period `2pi`. Therefore, the correct expression is `y=sin((2pi)/(lambda)x-(2 pi)/(T)t)` where `lambda` and T are wavelength and time period, respectively. In general, `y(x, t)=A sin(kx-omega t)`
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