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0.2 m aqueous solution of KCI freezen at...

`0.2 m` aqueous solution of KCI freezen at `-0.68^(@)C` calculate van't Hoff factor. `k_(1)` for water is `1.86 K kg mol^(-1)`.

Text Solution

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`i= ("observed property")/("Theoritical property (calculated)")`
Given `triangle T_(f)= 0.680 K, m= 0.2 m`
`triangleT_(f)` (observed) `= 0.680K`
`triangle T_(f)` (calculated) `=K_(f)*m`
`= 1.86 K Kg mol^(-1)xx 0.2 mol Kg^(-1)`
`= 0.372 K`
`i= ((triangle T_(f))"observed")/((triangleT_(f))("calculated"))= (0.680K)/(0.372K)= 1.82`.
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