`dy/dx`=`cosax`

dy/dx-y = cosx

-siny dy/dx = cosx

dy/dx = cos^2x

Solve: (dy)/(dx)+y=cosx

Solve: (i) sin^(-1)((dy)/(dx))=x+y (ii) (dy)/(dx)=cos(x+y) (iii) (dy)/(dx)=(4x+y+1)^2

dy/dx - y = cosx

Find dy/dx if x=cosy

Find the order and degree of the following differential equations. i) (dy)/(dx)+y=1/((dy)/(dx)) , ii) e^(e^(3)y)/(dx^(3))-x(d^(2)y)/(dx^(2))+y=0 , iii) sin^(-1)(dy)/(dx)=x+y , iv) log_(e)(dy)/(dx)=ax+by v) y(d^(2)y)/(dx^(2))+x((dy)/(dx))^(2)-4y(dy)/(dx)=0

Solve: (dy)/(dx)=e^(x+y) (ii) log((dy)/(dx))=a x+b y

Solve: x+y dy/dx=(a^2((x dy/dx-y))/(x^2+y^2))