`dy/dx``=``frac{x^2+y^2+1}{2xy}``

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dy/dx = frac{x^2+y^2}{2x^2}

dy/dx = frac{x^2-(1-2x)y}{x^2}

dy/dx = frac{2x+y}{x}

dy/dx = frac{cos^2y}{x(x^4+1)}

dy/dx + frac{1-2x}{x^2} y = 1

dy/dx = cos frac{x}{2} / 2

Solve: dy/dx + frac{1-2x}{x^2} y =1

dy/dx+2xy=e^(-x^2)

dx/dy = frac{x}{y-xy^3(1+cosx)}

Find (dy)/dx, if (x^2+y^2)^2=xy