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Can we use Norton’s theorem on a circuit...

Can we use Norton’s theorem on a circuit containing a BJT?
a) Yes
b) No
c) Depends on the BJT
d) Insufficient data provided

Text Solution

Verified by Experts

(a) Relative humidity
` =(VP/(SVP at (15^@C)))`
` rArr 0.4 = VP/(1.6 xx (10^3))`
` rArr VP = 0.4 xx 1.6 xx (10^3)`
The evaporation occurs as long as the
atmosphere does not saturated
Net pressure change
`= 1.6 xx (10^3) - 0.4 xx 1.6 xx (10^3)`
` = (1.6 - 0.4 xx 1.6 )(10^3)`
` 0.96 xx (10^3).`
Mass of water evaporated =m
` rArr 0.96 xx (10^3) xx 50 = ((m xx 8.3 xx 288) /18)`
` rArr m = (0.96 xx 50 xx 18 xx (10^3)/ 8.3 xx 288)`
` = 361.45 ~~ 361 g .`
` (b) At `20^@C`, SVP = 2.4 K Pa,
` At 15^@C, SVP = 1.6 K Pa.`
Net pressure change
`= ( 2.4 xx 1.6) xx (10^3) Pa`
`= 0.8 xx (10^3) Pa`
Mass of water evaporated
` m= (m' xx 8.3 xx 293 / 18)`
` rArr m' = (0.8 xx 50 xx 18 xx (10^3)/ 8.3 xx 293)`
` = 296.06 ~~296 grams .`
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