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Young's modulus of steel is 19xx10^10 N/...

Young's modulus of steel is `19xx10^10 N/m^2`. Expres it indyne/cm^2. Here dyne is the CGS unit of force.

Text Solution

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The unit Young's modulus is `N/m^2`. This suggests that it has dimensions of `Force/((distance)^2)`
Thus, `[Y]= [F]/L^2= (MLT^-2)/L^2=ML^-1T^-2`. ltbr. `N/m^2` is in SI units.
So, `1 N/m^2=(1kg)(1m)^-1(1s)^-2`
and `1 dyne/cm^2= (1g)(1cm)^-1(1s)^-2`
so, ` (1N/m^2)/(1dyne/cm^2)=((1kg)/(1g))/((1m)/(1cm)^_1((1s)/(1s)^-2`
`=1000xx1/100xx1=10`
or, `1N/m^2= 10 dyne/cm^2`
`or, 19xx10^10 N/m^2= 19xx10^11 dyne/cm^2`.
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