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IF veca=2veci+3vecj+4veck and vecb =3vec...

IF `veca=2veci+3vecj+4veck and vecb =3veci+4vecj+5veck` find the angle between `veca and vecb`.

Text Solution

Verified by Experts

The correct Answer is:
`cos^-1((38)/sqrt(1450))`
Here `veca=2veci+3veci+4veck`
and`vecb=3veci+4vecj+5veck`
`veca.vecb=abcostheta`
`theta= cos^-1((veca.vecb)/(ab))`
=`cos^-1 (2xx3+3xx4+4xx5)/(sqrt(2^2+3^2+4^2)sqrt(3^2+4^2+^2))
=cos^-1 ((38)/(sqrt(29)sqrt(50)))
= cos^-1 ((38)/sqrt(1450))`
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