For high frequencies, capacitor acts as _________
a) Open circuit
b) Short circuit
c) Amplifier
d) Rectifier

Answer

A, B, D

Explanation

Given `vecF`=`qvecE`+`q(vecvxxvecB`)=0

rarr E=-(vecvxxvecB)`
So the direction of `vxxB` should be opposite to the direction of `vecE. Hence vecv` should be in the +e yz-plane.
Again
`e=v B sin theta, rarr v=E/B sin theta` For v to be minimum
`theta = 90^0 and s v_(mn)=E/B`
So, the partilce must be projected at minimum speed of `E/B` along \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\'-\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\' ve z- axis `(theta =90^0) as shown in the figure so that the force is zero.