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For very low frequencies, capacitor acts...

For very low frequencies, capacitor acts as ________
a) Open circuit
b) Short circuit
c) Amplifier
d) Rectifier

Text Solution

Verified by Experts

The correct Answer is:
(a)2/e (b)-20/3e (c)5.8/3e
Equation `i =i_0.e^(-t/RC), where
i_0=2A, R=6x10^5 ohm
C=0.0500xx10^(-6)F
=5x10^(-7)F
=5xx10^(-7)F
i=2.0 e^)-t/0.3)
a. i=2xxe^(-1)= 2/e amp.
b.di/dt=(-i_0)/RC.e^(-t/RC)
when t=0.3 sec, then di/dt=2/(0.3) e^)(-0.3)/(0.3))(-20)/(3e) amp/sec
c. At t= 0.31 st
i= 2e((-0.3)/0.3), 5.8/(3e) amp (approx.)
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