Home
Class 11
PHYSICS
A ball is thrown up at a speed of 4.0 m/...

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take `g=10 m//s^2`.

Text Solution

Verified by Experts

Let us take vertically upward direction as the positive Y-axis. We have `u=4.0 m/s and a=-10m/s^2`. At the highest point the velocity becomes zero.Using the formula.
`v^2=u^2+2ay`,
`0=(4.0 m/s)^2+2(-10 m/s^2)y` ltbrlt or, `y=(16 m^2/s^2)/(30 m/s^2)=0.80 m`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A ball is projected vertically up with a speed of 50 m/s. Find the maximum height , the time to reach the maximum height, and the speed at the maximum height (g=10 m//s^(2)) (AS_(1))

A ball is thrown in vertically upward direction. It returns back to the same position in 2s. Then the maximum height achieved by the ball is ...... (Take g = 9.8 ms^(-2) )

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed 40 m/s. Calculate the relative speed of the balls as a function of time.

A ball is fallen freely from top of tower of height 100 m and another ball is thrown upwards with 50 m/s at the same time when they will cross each other ? (g = 10 m//s^(2))

A ball is thrown upward and attains the maximum height 10 m. The initial velocity of this ball would be ……... ms^(-1)

A body is thrown up with a kinetic energy of 10 J. If it attains maximum height of 5 m, then find its mass. (g=10ms^(-2))

A rocket is fired vertically up from the ground with a resultant vertical acceleration of 10 m//s^2. The fuel is finished in 1 min and it continues to move up. (a) What is the maximum height reached? (b) Afte2r how much time from then will the maximum height be reached?(Take g= 10 m//s^2 )