Home
Class 11
PHYSICS
Two projectiles A and B are projected wi...

Two projectiles A and B are projected with angle of projection B. If `R_A and R_B` be the horizontal range for the two projectile then.

A

`R_AltR_B`

B

`R_A=R_B`

C

`R_AgtR_B`

D

the information is insufficient to decide the relastion of `R_A with R_B`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The angle of projection at which the horizontal range and maximum height of projectile are equal is

Galileo writes that for angles of projection of a projectile at angles (45 + theta) and (45 - theta) , the horizontal ranges described by the projectile are in the ratio of (if theta le 45 )

A projectile can have the same range R for two angles of projection. If t_(1) and t_(2) be the times of flight in the two cases:-

Two balls A and B are thrown with speeds u and u//2 , respectively. Both the balls cover the same horizontal distance before returning to the plane of projection. If the angle of projection of ball B is 15^@ with the horizontal, then the angle of projection of A is.

Maximum range of projectile depend on angle of projectile.

A projectile can have the same range 'R' for two angles of projection . If 'T_(1)' and 'T_(2)' to be times of flights in the two cases, then the product of the two times of flights is directly proportional to .

Two projectiles are projected with velocity v_(A), v_(B) at angles theta_(A) (from horizontal) and theta_(B) (from vertical) as shown in the figure below, such that v_(A) gt v_(B) but having same horizontal component of velocity. Which of the following is correct ?

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to below in the direction of motion of the projectile, giving it a constant horizontal acceleration =g//2 . Under the same conditions of projection. Find the horizontal range of the projectile.

The velocity of projection of oblique projectile is (6hati+8hatj)ms^(-1) The horizontal range of the projectile is

Two projectiles are projected at angles ( theta) and ((pi)/(2) - theta ) to the horizontal respectively with same speed 20 m//s . One of them rises 10 m higher than the other. Find the angles of projection. (Take g= 10 m//s^(2) )