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A person travelling at 43.2 km/h applies...

A person travelling at 43.2 km/h applies the brake giving a deceleration of `6.0 m/ss^2` to his scooter. How far will it travel before stopping?

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The correct Answer is:
A, B
Initial velocity `u=43.2 km/hr= 12 m/s
u=12 m/s
v=0
a=6m/s^2 (Deceleration)
Distance
S= (v^2-u^2)/(2(-a))
=(0-(12)^2)/(2)-6))
=(12xx12)/12=12m`
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