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A particale is projected with a speed u ...

A particale is projected with a speed u at an angle `theta` with horizontal. Find the average velocity of projectile for the period during which it crosses half of maximum height.

Text Solution

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Time flight,
`T= (2usintheta)/g`
Average velocity
`=` (change in displcement)/Time `

Form the ure it can be said that the AB is horizontal. So there isno effect of vertical component of the velocity during this displacement.As teh body moves at a cionstant displacement, `u cos theta` in horizontal directiion, the average velocity during this displacement will be u cos theta in the horizontal direction.
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