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A river 400m wide is flowing at a rate o...

A river 400m wide is flowing at a rate of 2.0 `ms^(-1)`. A boat is salling at a speed of `10 ms^(-1)` w.r.t. water, in a direction perpendiuclar to the river.
(a) Find the time taken by the boat to reach the oppposite bank.
(b) How far from the point directly opposite to the starting point does the boat reach the opposite bank.

Text Solution

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The correct Answer is:
A, B, D

Here the boat moves with the resultant velocity r, but the vertical component 10 m/s takes him to the opposite shore.
`tan theta = 2/10 = 1/5`
` Velocity = 10 m/s`
`Distance = 400 m`
`Time = 4008/10 = 40 sec`

b. The boat will reach the point C.
In `/_\ABC, tan theta = (BC)/(AB)= (BC)/400= 1/5`
`rarrBC= 400/5=80 m`
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