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When a charged particle moves at right a...

When a charged particle moves at right angles to the magnetic field, the variable quantity is?
a) Momentum
b) Speed
c) Energy
d) Moment of inertia

Text Solution

Verified by Experts

The force on the rod A due to the charge +q of the rod B
=- q^2/(4pi eplsilon_0(l+a0^2)+q^2/(4 pi eplsilon_0 a^2)`
towards right. The force on this rod due to the charge -q.
`q^2/(4 pi eplsilon_0(2l+a)^2) - q^2/(4 pi epsilon_0(l+a)^2)`
towards right.
The resultan force on the rod is
`F= q^2 /(4 pi epsilon_0) [1/a^2-2/((l+a)^2)+1/((2l+a)^2)`]` towards right.
If `lgtgta`, the last two terms in the square bracket are negligible as compared to the first term. then,
`F~~q^2/(4pi epsilon_0 a^2)`
If `agtgt1`
`F=q^2/(4 pi eplsilon_0) [1/a^2-2/a^2+1/a^2]~~0`
Two neutral object placed far away exert only negligible force on each other but when they are placed closer they may exert appreciable force.
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