Home
Class 11
PHYSICS
In a TV pictgure tubeelectrons re ejecte...

In a TV pictgure tubeelectrons re ejected from the cathode with negligible speed and reach a velocity of `5x10^6` m/s in travelling one centimeter. Assuming straight line motion, find the constant force exerted on the electron. The mass of the electron is `9.1xx10^-31` kg.

Text Solution

Verified by Experts

Given, Initial velocity, u=0 (negligible),
`v= 5xx10^6 m/s`
` S=1cm 1xx 10^-2 m`
`:. Aceleration, a= (v^2-u^2)/(2S)`
` =((5xx10^5)^2-0)/(2xx1xx10^-3)`
(25xx10^1)/(2xx10^02)`
`=12.5xx10^14 m/s^2`
And Force, F=ma
`=9.1xx10^-31xx12.5xx10^-14`
`=113.75xx10^-12` ltBrgt ` =1.1xx10^-15 N`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Find velocity of particle with 1 mg mass and having same wavelength that of electron moving with speed of 3xx10^(6) m/s. Mass of electron 9.1xx10^(-31) kg

Electrons are emitted from photo-cell with maximum speed of 4xx10^(8) cm/s .Its stopping potential will be….. (Mass of electron =9xx10^(-31) kg.

A very long straight wire carries a current of 5 A. An electron moves with a velocity of 10^(6)ms^(-1) remaining parallel to the wire at a distance of 10 cm from wire in a direction opposite to that of electric current. Find the force on this electron. (Here the mass of electron is taken as constant) (e=-1.6xx10^(-19)C,mu_(0)=4pixx10^(-7)SI)

Calculate the wavelength of electron if its kinetic energy is 3.0xx10^(-25) J. Mass of electron is 9.1xx10^(-31) kg. (h = 6.626xx10^(-34) JS)

An electron moving with the speed 5 xx 10^6 m per second is shooted parallel to the electric field of intensity 1 xx 10^3 N/C. Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant, (mass of e = 9.1 xx 10^(-31) kg)

An electron in an atom is revolving round the nucleus in a circular orbit of radius 5.3 xx 10^(-11) m, with a speed of 2 xx 10^(6) ms^(-1) . The resultant orbital magnetic moment and angular momentum of the electron is ...... Take charge of electron = 1.6 xx 10^(-19) C , mass of electron = 9.1 xx 10^(-31) kg.

Electron is rotating in circular orbit with radius 5.2xx10^(-11)m and with linear speed 2xx10^(6)ms^(-1) in an hydrogen atom around the proton. Find the magnetic field produced at the centre of the orbit.

In an atom, an electron is moving with a speed of 600 m//s with an accuracy of 0.005% . Certainty with which the position of the electron can be localized is : ( h = 6.6 xx 10^(-34) kg m^2 s^(-1) , mass of electron (e_m) = 9. 1 xx10^(-31) kg) .

Calculate the uncertainty in the position of an electron if the uncertainty in its velocity is 5.7 xx 10^5 m//sec (h = 6.626 xx 10^(-34) kg m^2 s^(-1) , mass of the electron = 9.1 xx 10^(−31) kg ).