What is the correct expression for the rms value of current?
a)` I_(rms)=I_m/2`
b) `I_(rms)=I_m/(√2)`
c)` I_(rms)=I_m/4`
d) `I_(rms)=I_m`

Explanation

Given, `m=5 kg of block a`
` ma= 10N`
`rarr a 10/5 = 2m/s^2` ltBrgt As there is no friction between A and B, when the block A mioves, block B remains t rest in its position.

Initial velocity of `a, u=0`
Distance to cover by B to separate out,
`S= 0.2 m`
`Acceleration , a= 2 m/s^2`
We know, `S= ut+ 1/2 at^2`
`rarr 0.2 = 0+1/2 xx 2t^2`
`rarr t^2 =0.2`
`rarr t=0.44 sec~~ 0.45 sec`.