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What is the correct expression of ω? a...

What is the correct expression of ω?
a) ω=2π
b) ω=2πf
c) ω=πf
d) ω=2f

Text Solution

Verified by Experts

Given Reset as
Here `sintheta_1 = 4/5`
We know `g sin theta_1 = a+T` …………i ltbgt Again , `sin theta_2 = 3/5`
We know, `T-gsin theta_2 -a=0`
`rarr T=g sin theta_2 +a` ……..ii.

From equations i. and ii.
`g sin theta_2+a+a-g sin theta_1 =0`
`rarr 2a=gsin theta_1 - g sin theta_2 `
` rarr a= g/5 xx 1/2`
`= g/10`
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