The resultant of two alternating sinusoidal voltages or currents can be found using ___________
a) Triangular law
b) Parallelogram law
c) Either triangular or parallelogram law
d) Neither triangular nor parallelogram law
The resultant of two alternating sinusoidal voltages or currents can be found using ___________
a) Triangular law
b) Parallelogram law
c) Either triangular or parallelogram law
d) Neither triangular nor parallelogram law
a) Triangular law
b) Parallelogram law
c) Either triangular or parallelogram law
d) Neither triangular nor parallelogram law
Text Solution
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Let the block `m_1` moves upward with accelerastion `a_1 ` and the two block `m_2 and m_3` have relative cceleration `a_2` due to the diffference of weight between them,
So, the actual acceleratin of the blocks `m_1 , m_2 and m_3` will be `a_1(a_1-a_2) and (a_1+a_2)` as shown
From ure 2, `T-1g-1a_2=0`....i.
From ure 3, `
` T/2 -2 g-2(a_1-a_2)=0` ........ii. `
From ure 4,
` T/2 -3g-3(a_1+a_2)=0` ........iii.
From equations I. and ii. elimiN/Ating T, we get,
`1g+1a_2=4g+4(a_1+a_2)`
`rarr 5a_2-4a_1=3g` ...........iv.
From equations ii and iii we get
` 2g+2(a_1-a_2)=3-3(a_1-a_2)`
`rarr 5a_1 +a_2=g` .........v.
Solving equations iv and v we get,
` a_1 = 2g/29`
`and a_2 =g-5a_1`
`= g-(10g)/29=(19g)/29`
So, `a_1 -a_2= (2g)/(17g)/29`
and `a_1+a_2 =(2g)/29+(19g)/29=(21g)/29`
So, acceleratiion of `m_1, m_2 and m_3` are ` `(19g)/29 (up) , (17g)/29` (down) and `(21g)/29 (down), respectively.
Again, from `u=0, S=20 cm= 0.2 cm and
` a_2= (19g)/29 [g=10 m/s^2]`
:. S=ut+1/2 at^2`
`rarr 0.2=1/2xx19/29gt^2`
` rarr t=0.25 sec` .
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