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A horizontal force of 20 N i sapplied to...

A horizontal force of 20 N i sapplied to a block of mass 4 kg resting on a rough horiozontal table. If the blcok does not move on the table, how much fricrtional force the table is applying on the block What can be said about the coefficient of static friction between the block and the table? Take ` g=10m/s^2`.

A

-20 N , greater than 0.5

B

-20 N , less than 0.5

C

-40 N , greater than 0.5

D

-50 N , equal to 0.5

Text Solution

Verified by Experts

The correct Answer is:
A
The situation is shown in ure. The forces on the block are

a. `4kgxx10 m/s^2=40N` downward by the earth,
b. N upward by the table
c.20 N towards right by the experiments and
d. f towards left by the table (friction).
As the block is at rest these forces should add up to zero. Taking horizontal and vertical components,
`f=20N and N=40N`
Thus, the table exerts a frictioN/Al (static) force of 20 n on the block in the direction oposite to theapplied force.
`flemu_sN, or Mu_sgef/N or mu_sge05.
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