A body of mass 15 Kg covers a distance of 10 m in 10s starting from rest under the influence of a force. What is the work done by the force on the body?

Explanation

Let m= mass of child `R-mg cos 45^0=0`
`R=mg cos 45^0 = mg/sqrt2`………..i
Net force acting on the boy due to whichit slides down `=mg sin 45^0 -mu R`
`=mg sin 45^0-mu mg cos 45^0`

`mxx10xx(1/sqrt2)-0.6xxmxx10xx(1/sqrt2)`
`=m(5sqrt2-3sqrt2)=mxx2xxsqrt2`
Accelertion `=Force /mass`
`=(m(2sqrt(2)/m`
`=2sqrt2m/s^2`