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A particle travels in a circle of radius...

A particle travels in a circle of radius 20 cm at a speed thast uniformly increases. If the speed changes from 5.0 m/s to 6.0 m/s in 2.0s, find the angular aceleration.

A

`12.5rads^2`

B

`3.5rads^2`

C

`2.5rads^2`

D

`4.5rads^2`

Text Solution

Verified by Experts

The correct Answer is:
C
The tangential acceleration is gilven by
` a_t=(dv)/(dt)=(v_2-v_1)/(t_2-t_1)`
`=(6.0-5.0)/2.0m/s^2=0.5m/s^2`
The angula accelerationis `alpha =a_t/r`
`=(0.5m/s^2)/(20 cm)=2.5rads^2`
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