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A body weights 98 N on a spring balance ...

A body weights 98 N on a spring balance at the north pole. What will be its weight recorded on the same scale if it is shifted to te equator? Use g=`GM/R^2=9.8m/s^2` and the radius of the earth R=6400 km.

Text Solution

Verified by Experts

At poles, the apparent weight is same as the true weight,
Thus
`98N=mg=m(9.8m/s^2)`
or, `m=10kg`
At the equator, the apparent weight is
`mg'=mg-momega^2R`.
The radius of the earth is 6400 km and the angular speed is
` omega=(2pi rad)/(24xx60xx60s) =7.27xx10^-5rad/s`
Thus,
`mg'=98N-(10 kg) (7.27x10^-5s^-1)^2)(6400km)`
``97.66N
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