A cylindrical bucket filled with water is whirled around in a vertical circle of radius r. What can be the minimum speed at the top of the path if water does not all out from the bucket ? If it continues with this speed, what normal contact force the bucket exerts on water at the lowest point of the path?
A cylindrical bucket filled with water is whirled around in a vertical circle of radius r. What can be the minimum speed at the top of the path if water does not all out from the bucket ? If it continues with this speed, what normal contact force the bucket exerts on water at the lowest point of the path?
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consider water as the system. At the top of the cfircle its acceleration towards the centre is vertically downward with magnitude `v^2/r`. The forces on water asre ure.
a. weight Mg downward and
b. normal force by the bucket, aslso downward

So, from Newton's second law
`Mg=N=Mv^2/r`
For water not to fall out from the bucket `Nge0`
Hence, `Mv^2/rgeMg or, v^2rarr=rg`
the minimum speed at the top must be `sqrt(rg)`
If the bucket continues on the circle with this minimum speed `sqrt(rg)` the forces at the bottom of theh path are
a. weight Mg downward and
b. normal contact force N by the bucket upward.
The acceleration is twoards the centre which is vertically upward, so
`N'-Mg=Mv^2/g`
`or, N'=M(g+v^2/r)=2Mg`
a. weight Mg downward and
b. normal force by the bucket, aslso downward

So, from Newton's second law
`Mg=N=Mv^2/r`
For water not to fall out from the bucket `Nge0`
Hence, `Mv^2/rgeMg or, v^2rarr=rg`
the minimum speed at the top must be `sqrt(rg)`
If the bucket continues on the circle with this minimum speed `sqrt(rg)` the forces at the bottom of theh path are
a. weight Mg downward and
b. normal contact force N by the bucket upward.
The acceleration is twoards the centre which is vertically upward, so
`N'-Mg=Mv^2/g`
`or, N'=M(g+v^2/r)=2Mg`
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