Home
Class 11
PHYSICS
The position vector of a particle in a c...

The position vector of a particle in a circular motion about the origin sweeps out equal area in equal time. Then the particle's :-

A

velocity remains constant

B

speed remains constant

C

accelertion remains constant

D

tangential accelertion remains constant

Text Solution

Verified by Experts

The correct Answer is:
B, D
Promotional Banner

Similar Questions

Explore conceptually related problems

The position vector of a particle in a circular motion about the origin sweeps out equal area in equal time. Its

What is the amplitude of particle executing uniform circular motion?

Read each statement below carefully and state , with reasons , if it is true or false : (a) The net acceleration of a particle in circular motion is always along the radius of the circle towards the centre (b) The velocity vector of a particle at point is always along the tangent to the path of the particle at that point (c ) The acceleration vector of a particle in uniform circular motion averaged over one cycle is a nul vector

Mention the centre of mass of three particles which are not in line but have equal masses.

Statement-I : When the direction of motion of a particle moving in a circular path is reversed the direction of radial acceleration still remains the same (at the given point). Statement-II : Particle revolves on circular path in any direction such as clockwise or anticlockwise the direction of radius accelerationis always towards the centre of the circular path.

The position x of a particle varies with time t as x=at^(2)-bt^(3) . The acceleration at time t of the particle will be equal to zero, where (t) is equal to .

Path traced by a moving particle in space is called trajectory of the particle. Shape of trajectiry is decided by the forces acting on the particle. When a coordinate system is associated with a particle motion, the curve equation in which the particle moves [y=f(x)] is called equation of trajectory. It is just giving us the relation among x and y coordinates of the particle i.e. the locus of particle. To find equation of trajectory of a particle, find first x and y coordinates of the particle as a function of time eliminate the time factor. The position vector of car w.r.t. its starting point is given as vec(r)=at hat(i)- bt^(2) hat(j) where a and b are positive constants. The locus of a particle is:-

The rate of doing work by force acting on a particle moving along x-axis depends on position x of particle and is equal to 2x. The velocity of particle is given by expression :-

Figure gives the x-t plot of a particle is one dimensional motion. Give the signs of position, velocity and acceleration of the particle at t = 0.3s

Three particles, each of the mass m are situated at the vertices of an equilateral triangle of side a . The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation a . Find the initial velocity that should be given to each particle and also the time period of the circular motion. (F=(Gm_(1)m_(2))/(r^(2)))