Home
Class 11
PHYSICS
Usually, what is the least count of a sc...

Usually, what is the least count of a screw gauge?
a) 0.01 cm
b) 0.001 cm
c) 0.1 cm
d) 1 mm

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
Given `v=36 km/hr`
`=10 m/s`
`r=20m, mu=0.4`
`The road is banked with angle
`theta=tan^-1 v^2/(rg)`
`=tan^-1 (100/(20xx10-)`
`=tan^-1 (1/2)`
or `tantheta=0.5`

when the car travels at a maximum speed, so that to slips upward `muR_1` acts downward As shown it ure.
`R_1-mgcostheta=(mv_1^2)/rsintheta=0`........i
and `muR_1+vmgsintheta-(mv_1^2)/rcostheta=0`.....ii
Solving equations we get,
`v_1=sqrt(rg(mu+tantheta)/(1-mutantheta))`
=sqrt(20xx10xx0.9/0.8`
`=15 m/s=54 km/hr

Similarly it fcan be proved that
Similarly it can be proved that
`v_2=sqrt(rg(tantheta-mu)/(sqrt(1-mutantheta)))`
`=sqrt(20xx10xx0.1/1.2`
`=4.08m/s=14.7km/hr`
So the possible speeds asre between 14.7 km/hr and 54 km/hr.
Promotional Banner

Similar Questions

Explore conceptually related problems

In searle's experiment, the diameter of the wire, as measured by a screw gauge of least count 0.001 cm is 0.500 cm. The length, measured by a scale of least count 0.1cm is 110.0cm. When a weight of 40N is suspended from the wire, its extension is measured to be 0.125 cm by a micrometer of least count 0.001 cm. Find the Young's modulus of the meterial of the wire from this data.

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of - 0.004 cm, the correct diameter of the ball is

A student measured the diameter of a wire using a screw gauge with least count 0.001cm and listed the measurement. The correct measurement is

In Column-I instrument and in Column-II their least count is given. Match them properly : {:("Column-I","Column-II"),("(1) Microscope","(a) 0.01 cm"),("(2) Micrometer screw gauge","(b) 0.001 cm"),(,"(c) 0.0001 cm"):}

The diameter of a wire is measured with a screw gauge having least count 0.01 mm . Out of the following the one which correctly expresses its diameter is

If the number of divisions on the circular scale is 100 and number of full rotations given to screw is 8 and distance moved by the screw is 4 mm, then what will be least count of the screw gauge ?

A vernier callipers has 20 divisions on the vernier scale which coincide with 19 divisions on the main scale. The least count of the instrument is 0.1 mm. The main scale divisions are of

In a vernier calliper, N divisions of vernier scale coincide with (N-1) divisions of main scale (in which division represent 1mm). The least count of the instrument in cm. should be

In a vernier calliper, N divisions of vernier scale coincide with (N-1) divisions of main scale (in which division represent 1mm). The least count of the instrument in cm. should be

Students I_(1),J_(1), J_(3) and I_(2) perform an experiment for measuring the acceleration due to gravity (g) using a simple predulum, they use different lengths of the pendulum and record time for different number of oscillations. The observations are shown in the table. Least count for length = 0.1 cm , least count for time = 1s {:("Students",underset("pendulum (cm)")("Length of the"),underset("oscillations(n)")("No.of"),underset("of pendulum (s)")("Time period")),(I_(1),100.0,20,20),(J_(1),400.0,10,40),(J_(1),100.0,10,20),(I_(1),400.0,20,40):} If P_(1),P_(2),P_(3) and P_(4) are the % error in g for students I_(1),J_(1),J_(3) and I_(2) respectively then -