Home
Class 11
PHYSICS
A block of mass m slides down a smooth v...

A block of mass m slides down a smooth vertical circular track. During the motion, the block is in

A

vertical equilibrium

B

horizontl equilibrium

C

radia equilibrium

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A force of 50N acts in the direction as shown in figure. The block of mass 5kg, resting on a smooth horizontal surface. Find out the acceleration of the block.

A block of mass m is placed on a smooth horizontal floor is attached to one end of spring. The other end of the spring is attached to fixed support. When spring is vertical it is relaxed. Now the block is pulled to wards right by a force F, which is being increased gradually. When the speing makes angle 53^(@) with the vertical, block leaves the floor. When blocks leaves the table, the normal force on it from table is

A block of mass m is placed on a smooth horizontal floor is attached to one end of spring. The other end of the spring is attached to fixed support. When spring is vertical it is relaxed. Now the block is pulled to wards right by a force F, which is being increased gradually. When the speing makes angle 53^(@) with the vertical, block leaves the floor. When the block leaves the table, the force F is :-

A block of mass m is placed on a smooth horizontal floor is attached to one end of spring. The other end of the spring is attached to fixed support. When spring is vertical it is relaxed. Now the block is pulled to wards right by a force F, which is being increased gradually. When the speing makes angle 53^(@) with the vertical, block leaves the floor. Force constant of the spring is :-

A block of mass m is placed on a smooth slope of angle theta . The whole system (slope + block) is moved horizontally with acceleration a in such a way that the block does not slip on the slope. Hence, a =………..

A block of mass m is placed on a smooth wedge of inclination theta . The whole system is accelerated horizontally, so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

A bullet of mass 50g moving with velocity 600m//s hits block of mass 1.0kg placed on a rough horizontal ground and comes out of the block with a velocity of 400m//s . The coefficient of friction between the block and the ground is 0.25 . Neglect loss of mass of the block as the bullet pierces through it. (a) In spite of the fact that friction acts a an external force, can you apply principle of conservation of momentum during interaction of the ullet with the block? (b) Find velocity of the block immediately after the bullet pierces through it. (c)FInd the distance the block will travel before it stops.

A block of mass 1kg lies on a horizontal surface in a turck, the coefficient of static fricition between the block and the surface is 0.6, what is the force of fricition on the block. If the acceleration of the truck is 5m//s^(2) .

In the figure shown, the block A of mass m collides with the identical block B and after collision they stick together. Calculate the amplitude of resulatant vibration.

A cubical block of mass m and edge a slides down a rough inclned plane of inclination theta with a uniform speed. Find the torque of the normal force acting on the block about its centre.