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Path length does not depend on a) Init...

Path length does not depend on ____
a) Initial point
b) Final point
c) Path taken
d) Coordinate system

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`L=1.5m, u=sqrt57 m/sec`
a. `mgcostheta=(mv^2)/L`
`v^2=Lgcostheta`
change in K.E.= work done
` 1/2 mv^2-1/2mu^2=mgh`
`rarr v^2-57=-2xx1.5g(1+costheta)` ……….ii
`rarr v^2=57-3g(1+costheta)`

Putting the value of v from equaltion i.
`15 cos theta-57-3g(1+costheta)`
`rarr 15 costheta=57-30-30 costheta`
`rarr 45costheta=27`
`rarr costheta =3/5`
`rarr theta=cos^-13/5=53^0`
b. `v=sqrt(57-3g(1+costheta))` from equation i
`sqrt9=e/sec.
c. as the string become slack at point B,the particle will start makign projection tile motion
`H=OF+DC`
`=1.5costheta+(u^2sin^2theta)/(2g)`
`(1.5)xx3/5xx(9xx(0.8)^2)/(2xx10)`
`1.2m`
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