Home
Class 11
PHYSICS
A body has its centre of maas at the ori...

A body has its centre of maas at the origin. The x-coordinates of the particles

A

may be all positive

B

may be all negative

C

may be all non negative

D

may be positive for some case and negative in other cases.

Text Solution

Verified by Experts

The correct Answer is:
C, D
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle of mass m is moving with constant speed v on the line y=b in positive x-direction. Find its angular momentum about origin, when position coordinates of the particle are (a, b).

Path traced by a moving particle in space is called trajectory of the particle. Shape of trajectiry is decided by the forces acting on the particle. When a coordinate system is associated with a particle motion, the curve equation in which the particle moves [y=f(x)] is called equation of trajectory. It is just giving us the relation among x and y coordinates of the particle i.e. the locus of particle. To find equation of trajectory of a particle, find first x and y coordinates of the particle as a function of time eliminate the time factor. The position vector of car w.r.t. its starting point is given as vec(r)=at hat(i)- bt^(2) hat(j) where a and b are positive constants. The locus of a particle is:-

A solid sphere of uniform density and radius 4 units is located with its centre at the origin O of coordinates. Two sphere of equal radii 1 unit, with their centres at A(-2,0 ,0) and B(2,0,0) respectively, are taken out of the solid leaving behind spherical cavities as shown if fig Then:

Path traced by a moving particle in space is called trajectory of the particle. Shape of trajectiry is decided by the forces acting on the particle. When a coordinate system is associated with a particle motion, the curve equation in which the particle moves [y=f(x)] is called equation of trajectory. It is just giving us the relation among x and y coordinates of the particle i.e. the locus of particle. To find equation of trajectory of a particle, find first x and y coordinates of the particle as a function of time eliminate the time factor. In above question initial acceleration (i.e. (d^(2)vec(r))/(dt^(2))) of particle is :-

Path traced by a moving particle in space is called trajectory of the particle. Shape of trajectiry is decided by the forces acting on the particle. When a coordinate system is associated with a particle motion, the curve equation in which the particle moves [y=f(x)] is called equation of trajectory. It is just giving us the relation among x and y coordinates of the particle i.e. the locus of particle. To find equation of trajectory of a particle, find first x and y coordinates of the particle as a function of time eliminate the time factor. In above the velocity (i.e. (dvec(r))/(dt)) at t=0 is :-

A body moves in anticlockwise direction on a circular path in the x-y plane. The radius of the circular path is 5m and its centre is at the origin. In a certain interval of time, displacement of the body is obesrved to be 6m in the positive y-direction. Which of the following is true ?

A circle has its centre at the origin and point P(5,0) lies on it. Then , the point Q(3,4) lies in the interior of the circle.

An electric field prevailing in a region depends only on x and y coordinates according to an equation vecE = b(xhati + yhatj)/(x^(2) + y^(2)) where & is a constant. Flux passing through a sphere of radius r whose centre is on the origin of the coordinate system is…………..

As a particle moves along the x- axis, it is acted upon by a conservative force. The potential energy is shown below as a function of the coordinate x of the particle. Rank the labelled regions accoeording to the magnitude of force, least to greatest.

A particle starts from the origin at t=0 s with a velocity of 10.0hatjm//s and moves in the x-y plane with a constant acceleration of (8.0hati+2.0hatj) " m s"^(-2) (a) At what time is the x - coordinate of the speed of the particle at the time ?