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Two particles of mass m each are attache...

Two particles of mass m each are attached to a light rod of length d, one at its centre and the other at a free end, The rod is fixed at the other end is rotated in a plane at an angular speed `omega`. Calculate the angular momentum of the particle at the end with respect to the particle at the centre

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The situation is shown in ure. The velocity of the particle with respect to the fixed end O is `v_A=omega(d/2)` and that of B with respect to O is `v_B=omegad`. Hence the velocity of B with respect to A is `v_B-v_A=omega(d/2). `the angular momentum of B with respect to A is therefore
`L=mvr=momega(d/2)=1/4momegad^2`
along the directiion perpendicular to the plane of rotation.
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