A body is in translational equilibrium under the sctin of coplanar forces. If the torque of these force is zero about a point is it necessary that it will also be zero abut any other point?

The vector sum of a system of non-collinear forces acting on a rigid body is given to be non-zero. If the vector sum of all the torques due to the system of forces about a certain point is found to be zero, does this mean that it is necessarily zero about any arbitrary point?

The gravitational potential energy of a body at a distance r from the center of the earth is U. The force at that point is :

f the net force acting on an object is zero, then the body is said to be in the state of

Assertion:- Net torque about point B is of all real forces is not zero. Reason:- Because it will rotate about point B.

Necessary condition of equilibrium is that acceleration of body should be zero.

Integration is zero for a point of homogeneous body. which is that point?

A wheel in uniform motion about an axis passing through its centre and perpendicular to its plane is considered to be in mechanical (translational plus rotational) equilibrium becaues no net external force or torque is required to sustain its motion. However, the particles that constitute the wheel do experience a centripetal the acceleration directed towards the centre. How do you reconcile this fact with the wheel being in equilibrium? How would you set a half wheel into uniform motion about an axis passing through the centre of mass of the wheel and perpendicular to its plane? Will you require external forces to sustain the motion?

Work done in the motion of a body over a closed loop is zero for every force in nature .

The distance x of a particle moving in one dimensions, under the action of a constant force is related to time t by the equation, t=sqrt(x)+3 , where x is in metres and t in seconds. Find the displacement of the particle when its velocity is zero.

A block of mass m is pulled by a uniform chain of mass m tied to it by applying a force F at the other end of the chain.The tension at a point P which is at a distance of quarter of the length of the chain from the free end,will be