the moment of inertia ofa uniform rod of mass 0.50 kg and length 1 m is 0.10 kg m^2 about a line perpendicular to the rod. Find the distance of this line from the middle point of the rod.

Answer

C, D

Explanation

Length of the rod=1m, Mass of the rod
`=0.5kg`
Let at distance d from the centre the rod is moving.
Applying parallel axis therom, the moment of inertia about that point
`rarr ((ml^2)/12)+md^2=0.10`

`rarr (0.5xxl^2)/12+0.5xxd^2=0.10` ltbr. `rarr 1/12+d^2=0.2`
`rarr d^2=0.118`
`d=0.342m from the centre