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Find the degree of the differential equa...

Find the degree of the differential equation ` ((d^3y)/dx^3)^2+y^2=0 `
a) 5
b) 4
c) 2
d) 1

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
According to the questions `m_1=200g, l=1m,m_2=20g`
Therefore
`(T_1xxr_1)-(T_2xxr_2)-(m_1gxxr_3)=0`
`rarr T_1xx0.7-T_2xx0.3-2xx0.2xxg=0`
`rarr 7T_1-3T_2=3.92` .....1
T_1+T_2=2xx9.8+0.02xx9.8`
`1.96+0.196=2.156`

`3T_1+3T_2=6.468`..........2
Adding 1 and 2 we get
`rarr 10T_1=10.3`
`rarr T_1=1.038N=1.04N`
Therefore `T_2=2.156-1.038`
`=1.18~=1.12N`
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