Home
Class 11
PHYSICS
A uniform rod of mass 300 g and length 5...

A uniform rod of mass 300 g and length 50 cm rotates at a uniform asngulr speed of 2 rad/s about an axis perpendicular to the rod through an end. Calculte a. the angular momentum of the rod about the axis of rotation b. the speed of thecentre of the rod and c. its kinetic energy.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
A uniform of rod mass 300 gm and length =50 cm rotates wilth a uniform angular velocity =2 rad/s abut an axis `_|_` to te rod through an end.
a. `L=Iomega`
`I at the end =(mL^2)/3=({0.3xx(0.5)^2})/3`
`=((.3xx0.25))/3`
`=0.075/3=0.025kg-m^2`
Therefore angular momentum about that point
`=0.025xx2`
`-=0.05kg-m^2/s`
b. Sped ofthe centre of rod
`V=omegar=2xx(50/2)`
`=50 cm/s=0.5m/s`
c. It kinetic energy
c. `1/2Iomega^2=(1/2)xx0.025xx2^2`
`=0.25joule
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the moment of inertia of a rod of mass M, length l about an axis perpendicular to it through one end?

A uniform rod of mass m and length l rotates in a horizontal plane with an angular velocity omega about a vertical axis passing through one end. The tension in the rod at a distance x from the axis is

A thin uniform metallic rod of length 0.5 m and radius 0.1 m rotates with an angular velocity 400rad/s is a horizontal plane about a vertical axis passing through one of its ends. Calculate (a) tenstion in the rod and (b) the elogation of te rod. The density of material of the rod is 10^(4)kg//m^(3) and the young's modulus is 2xx10^(11)N//m^(2)

A thin uniform rod of mass .M. and length .L. rotates with constant angular velocity .omega. about perpendicular axis passing through its centre. Two bodies each of mass (M)/(3) are attached to its two ends. What is its angular velocity?

A metallic rod of length I rotates at angular velocity omega about an axis passing through one end and perpendicular to the rod. If mass of electron is m and its charge is -e then the magnitude of potential difference between its two ends is

If I_(1) is the moment of inertia of a uniform rod about an axis perpendicular to its length and passing through its one end. Now ring formed by bending the rod, if the moment of inertia about the diameter of ring I_(1) then (I_(1))/(I_(2)) = ……….

Four identical thin rods each of mass M and length l from a square frame. Moment of inerita of this frame about an axis through the centre of the square and perpendicular to its plane is ……………

A uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly

The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint and perpendicular to its length is I_(0) . Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is .............