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Find the differential equation of y=3x^...

Find the differential equation of `y=3x^2`?

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The correct Answer is:
A
Angular momentum due to the mass `m_1 ` at the centre of system
`=m_1((m_2r)/(m_1+m_2))^2omega`
=(m_1m_2^2r^2)/((m_1+m_2)^2)` ………1
similarly, the angular momentum due the mass `m_2` at the centre of system
`=m_2=((m_1r)/(m_1m_2)^2)` omega`
`=(m_2m_1^2r_2)/((m_1+m_2)^2)omega`..........2
Therefore net angular momentum
`=(m_1m_2^2r^2omega)/((m_1+m_2)^2)+(m_2m_1^2r^2omega)/((m_1+m_2)^2)`
`=(m_1m_2(m_1+m_2)r^2omega)/((m_1+m_2)^2)`
`=(m_1m_2)/((m_1+m_2))r^2omega
`=mur^2omega` Proved
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