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Find the degree of the D.E (y’’)^2+25y’=...

Find the degree of the D.E `(y’’)^2+25y’=0`.
a) 1
b) 2
c) 4
d) 3

Text Solution

Verified by Experts

The correct Answer is:
A, B
Let the mass of the particle =m
and the mass of the rod =M
Let the particles stirke the rod with as velocity V.
If we take two body to be a system.
Therefore the net externla torque and exterN/Al force =0


Therfore applying laws of conservation of linear momentum
`MV'=mV`
`(V'=velocity of the rod after striking)
`rarrV'/V=m/M`
Again applying laws of conservatioin of angular momentum
`rarr (mVR)/2=I omega`
`-(mVR)/2=((MR^2)/12)xx(pi/(2t))`
`t=((MRpi)/(mxx12xxV))`

`Therefore distance travelled
`=Vt=V'(Mrpi)(m12pi)`
`=(m/M)xx(M/m)xx((RPi)/12)`
`=(Rpi)/12`
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