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Find the angle between the two vectors v...

Find the angle between the two vectors `veca` and `vecb` with magnitude √3 and √2 respectively and `veca` . `vecb` =3√2.
`a) cos^(−1)(1/(√3))`
`b)cos^(−1)√3`
`c) cos^(−1)(3/(√2))`
`d) cos^(−1)(2/(√3))`

Text Solution

Verified by Experts

The correct Answer is:
A
Total normal force `=mg+(mv^2)/(R-r)`
`Agin, mg(R-r)=1/2Iomega^2+1/2 mv^2`

`mg(R-r)=1/2x2/5mv^2+1/2mv^2`
rarr 7/10mv^2=mg(R-r)`
`rarr v^2=10/7g(R-r)` Therefore, total normal force
`=mg(m(10/7)g(R-r))/(R-r)`
`=mg+mg(10/7)`
`-(17/7)mg`
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