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The particles of mases 1kg and 2 kg are ...

The particles of mases 1kg and 2 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of heavier particle.

Text Solution

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The force of gravitastion exerted by one particle on another is
`F_1=(Gm_1m_2)/r^2`
`=96.67xx10^-11(N-m^2)/(kg^2)(1.0kg)xx(2.0kg))/((0.5m)^2)`
`=5.3xx10^-10N`
The acceleration of 1.0 kg particle is
`a_`=F/m_1=(5.3xx10^-10N)/(1.0kg)`
`=5.3xx10^-10N ms^2-`
This acceleration is towards the 2.0 kg particle. The acceleration of the 2.0 kg particle is
`a_2=F/m_2=(5.3xx10^-10N)/(2.0kg)`
`=2.65xx10^-10ms^-2`
This acceleration is towards the 1.0 kg particle.
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