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The gravitational field due to a mass di...

The gravitational field due to a mass distribution is `E=(K)/(x^(3))` in the x-direction. (K is constant) taking of gravitaional potential to be zero at infinity, its value at the distance x is

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The potential at a distance x is
`V(x)=-int_oo^x E dx=-int_oo^x K/x^3 dx`
`=[K/(2x^2)]_oo^x=K/(2x^2)`
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