Home
Class 11
PHYSICS
The gravitational potential due to a mas...

The gravitational potential due to a mass distribution is `V=A/sqrt(x^2+a^2)`. Find the gravitational field.

Text Solution

Verified by Experts

V=A/sqrt(x^2+a^2)=A(x^2+a^2)^(-1/2)`
If the gravitatioN/Al field is E.
`E_x=(delV)/(delx)=-A(-1/2)(x^2+a^2)^(-3/2)(2x)`
=(Ax)/((x^2+a^2)^(3/2))`
`E_y=-(delV)/(dely)=0 and E_z=-(delV)/(delZ)=0`
the gravitatioN/Al field is `(Ax)/((x^2+a^2)^(3/2))` in the x direction.
Promotional Banner

Similar Questions

Explore conceptually related problems

The gravitational potential energy is maximum at :

The gravitational field due to a mass distribution is given by E=K/x^3 in X-direction. Taking the gravitational potential to be zero at infinity, find its value at a distance x.

Write an equation for potential due to linear charge distribution.

Gravitational potential is negative it does it mean?

Write an equation for potential due to volume charge distribution.

Two bodies of masses m and 4m are placed at a distance r. The gravitational potential at a point on the line joining them where the gravitational field is zero is:

The gravitational potential energy of a body of mass m at the earth's surface is mgR_e . Its gravitational potential energy at a height R_e from the earth's surface will be ..... (Here R_e is the radius of earth)

Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V is

As shown in figure , four masses each of mass 3sqrt2 kg at the corners of a square of side 3 m . Calculate the gravitational potential energy of system of these four particles. Also calculate the gravitational potential at the centre of square. (G = 6.67 x 10^(-11) SI unit)

If the gravitational potential at the earth's surface is de What is the gravitational potential at a height from earth's surface equal to its radius?