Can two particles be in equilibrium under the action of their mutual gravitational force? Can three particle be? Can one of the three particles be?

What is gravitational force on a particl at the centre of earth ?

Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Four particles, each of mass M and equidistant from each other, move along a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is:

Two particles of equal mass 'm' go around a circle of radius R under the action of their mutual gravitaitonal attraction. The speed of each particle with respect to their centre of a mass is -

Four particles, each of mass M and equidistant "from each other, move along a circle of radius R under the action of the mutual gravitational attraction. The speed of each particle is ......... (G = universal gravitational constant)

Two particles of equal mass m move around a circle of radius R under the influence of their mutual gravitational attraction, the speed of each particle with respect to their center of mass will be ..........

A particle of mass m is tied to light string and rotated with a speed v along a circular path of radius r. If T=tension in the string and mg= gravitational force on the particle then actual forces acting on the particle are

Three particles, each of mass m and carrying a charge q each, are suspended from a common point by insulating mass-less strings each of length L. If the particles are in equilibrium and are located at the corners of an equilateral triangle of side a, calculate the charge q on each particle. Assume Lgtgta .

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

Three particles, each of the mass m are situated at the vertices of an equilateral triangle of side a . The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation a . Find the initial velocity that should be given to each particle and also the time period of the circular motion. (F=(Gm_(1)m_(2))/(r^(2)))