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The resultant force acting on a particle...

The resultant force acting on a particle executing simple harmonic motion is 4N when it is 5cm away from the centre of oscillation. Find the spring constant.

Text Solution

Verified by Experts

The simple harmonic motion is defilned as ltbr. `F=-kx`
The spring constant is `k=|F/x|`
`=(4N)/(5cm)=(4N)/(5xx10^-2m)=80Nm^-1`
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