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A particle of mass 40 g executes a simpl...

A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.

Text Solution

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The total mechanical energy of the system is
`E=1/2momega^2A^2`
`=1/2m((2pi)/T)^2A^2=(2pi^2mA^2)/T^2`
`=(2pi^2(40xx10^-3kg)(2.0xx10^-2m)^2)/(0.20s)`
`=7.9xx10^-3J`.
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