Home
Class 11
PHYSICS
The equation of a prticle executing simp...

The equation of a prticle executing simple harmonic motion is `x=(5m)sin[(pis^-1)t+pi/3].` Write down the amplitude time period and maximum speed. Also find the velocity at t=1s.

Text Solution

Verified by Experts

Comparing with equation `x=Asin(omegat+delta)` se see that
the amplitude `=5m`
and time period `=(2pi)/omega=(2pi)/(pis^-1)=2s`
The maximum speed `=Aomega=5xmmpis^-1=5pims^-1`
the velocity at time `t=(dx)/(dt)=Aomega cos (omegat+delta)`.
At t=1s,
`v=(5m)(pis^-1)cos(pi+pi/3)=-(5pi)/3ms^-1`
Promotional Banner

Similar Questions

Explore conceptually related problems

The maximum velocity of a particle executing simple harmonic motion with an amplitude 7 mm is 4.4 m/s. The period of oscillation is.

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=1s ?

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=0 ?

The particle executes simple harmonic motion have periodic time 0.05s and amplitude 4 cm, then what its maximum velocity?

The acceleration of a certain simple harmonic oscillator is given by a=-(35.28 m//s^(2))cos4.2t The amplitude of the simple harmonic motion is

The displacement of a particle executing simple harmonic motion is given by y= A_(0) +A sin omega t+ B cos omega t . Then the amplitude of its oscillation is given by:

The x-t graph of a particle undergoing simple harmonic motion is shown in figure. Acceleration of particle at t = 4//3 s is

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm"/"s . The frequency of its oscillation is……….

The equation of simple harmonic is as following y(t) = 10 sin (20t+ 45^(@)) . Find the amplitude of SHM.