Home
Class 11
PHYSICS
Mass of the body is 3kg and acceleration...

Mass of the body is `3kg` and acceleration is ` 5m/s^2` then force of body is

Text Solution

Verified by Experts

The block reaches the sring with a speed v. It now compresses te spring . The block is decelerated due toteh sprng force comes to rest when `1/2mv^2=1/2kx^2` and returns back. It is accelerated due toteh spring force till the spring acquires its N/Atural length. The contact of the block with the spring is now broken. At this instant it has regained its speed v (towards left) as teh sprig is unstretched and no potential energy is stored. This proces takes half the period of oscillation, i.e. `pisqrt(m/k)`. The block strikes the left wall after a time `L/v` and as the collision is elstic it rebounds with the same speed v. After a time `L/v`, it again reaches the spring and the process is repeated. The block thus undergoes periodic motion with time period `pisqrt(m/k)+(2L)/v`
Promotional Banner

Similar Questions

Explore conceptually related problems

if mass of body is 20kg and momentum is 40Ns then velocity of moving body is

A 2 kg block A is attached to one end of a light string that passes over an an ideal pulley and a 1 kg sleeve B slides down the other part of the string with an acceleration of 5m//s^(2) with respect to the string. Find the acceleration of the block, acceleration of sleeve and tension in the steing. [g=10m//s^(2)]

Two bodies of masses 4 kg and 5kg are acted upon by the same force. If the acceleration of lighter body is 2m//sec^(2) , then the acceleration of the heavier body is:-

If a body with mass(2kg) moving with acceleration that is equal to 5m/s^2 then what is the value of force experienced by body?

A particle of mass m_(0) is projected from the surface of body (1) with initial velocity v_(0) towards the body (2). As shown in figure find the minimum value of v_(0) so that the particle reaches the surface of body (2). Radius of body (1) is R_(1) and mass of body (1) is M_(1) . Radius body (2) is R_(2) and mass of the body (2) is M_(2) distance between te center the center of two bodies is D.

A force F applied to an object of mass m_(1) produces an acceleration of 3.00m//s^(2). The same force applied to a second object of mass m_(2) produces an acceleration of 1.00m//s^(2). (i) What is the value of the ratio m_(1)//m_(2) ? (ii) If m_(1) and m_(2) are combined, find their acceleration under the action of the force F.

The potential energy of a body mass m is U=ax+by the magnitude of acceleration of the body will be-

When 10 N force act on a body, 1ms^-2 acceleration is produced on it. Mass of body will be …...